Question

Plz solve this !!! It is my Assignment question?

Answer 1

Answer:

Median = 19.5

Step-by-step explanation:

Class         f        cf

5-10         5         5

10-15        6         11

15-20       15       26

20-25      10       36

25-30       5        41

30-35        4       45

35-40        2      47

40-45        2     49

Here,

N = 49

==> (N/2) = 49/2 = 24.5

Median class is 15 - 20.

Here, l = 15, c.f = 11, f = 15, h = 5

Median = l + (N/2 - cf/f) * h

==> 15 + (24.5 - 11/15) * 5

==> 15 + (13.5/15) * 5

==> 19.5

Result :

Median = 19.5

#BeBrainly

Answer 2

❏ Solution:-

$<!-- Codes by HTML.am --></p><p></p><p><!-- CSS Code --></p><p><style type="text/css" scoped></p><p>table.GeneratedTable {</p><p>width:100%;</p><p>background-color:#FFFFFF;</p><p>border-collapse:collapse;border-width:1px;</p><p>border-color:#336600;</p><p>border-style:solid;</p><p>color:#009900;</p><p>}</p><p></p><p>table.GeneratedTable td, table.GeneratedTable th {</p><p>border-width:1px;</p><p>border-color:#336600;</p><p>border-style:solid;</p><p>padding:3px;</p><p>}</p><p></p><p>table.GeneratedTable thead {</p><p>background-color:#CCFF99;</p><p>}</p><p></style></p><p></p><p><!-- HTML Code --></p><p><table class="GeneratedTable"></p><p><thead></p><p><tr></p><p><th>Class Interval</th></p><p><th>Frequency</th></p><p><th>Step-arithmatic frequency (Lower index)</th></p><p></tr></p><p></thead></p><p><tbody></p><p><tr></p><p><td>5-10</td></p><p><td>5</td></p><p><td>5</td></p><p></tr></p><p><tr></p><p><td>10-15</td></p><p><td>6</td></p><p><td>5+6=11</td></p><p></tr></p><p><tr></p><p><td>15-20</td></p><p><td>15</td></p><p><td>11+15=26</td></p><p></tr></p><p><tr></p><p><td>20-25</td></p><p><td>10</td></p><p><td>26+10=36</td></p><p></tr></p><p><tr></p><p><td>25-30</td></p><p><td>5</td></p><p><td>36+5=41</td></p><p></tr></p><p><tr></p><p><td> 30-35</td></p><p><td>4</td></p><p><td>41+4=45</td></p><p></tr></p><p><tr></p><p><td>35-40</td></p><p><td>2</td></p><p><td>45+2=47</td></p><p></tr></p><p><tr></p><p><td>40-45</td></p><p><td>2</td></p><p><td>47+2=49</td></p><p></tr></p><p><tr></p><p><td> </td></p><p><td>N=49</td></p><p><td> </td></p><p></tr></p><p></p><p></tbody></p><p></table>$

➝ Total frequency=N=49

✰So, the median-class term is

=49/2

=24.5'th term

✦median-class is = 15-20

$\therefore \boxed{ \bf\red{median=l + (\frac{ \frac{N}{2} -c_f }{f} ) \times h}}$

$\bf\rightarrow l=lower\: class\: boundary\: of\: median \:class\:\\ \bf\rightarrow N=number\: of\: frequency\\ \bf\rightarrow f=number\: of\: frequency\: of\: median \:class \\ \bf\rightarrow h=class \:length\: of\: median\: class\\ \bf \rightarrow c_f=step\: arithmetic \:frequency\: of\: the\:\\ \bf previous\: class\: just \:the \:median\: class.$

•Given(from the data frequency table):-

$\rightarrow l=15\\ \rightarrow N=49\\</p><p>\rightarrow f=15 \\ \rightarrow h=5\\</p><p>\rightarrow c_f=11$

•Putting the values:-

$\sf\therefore \bf median=15 + (\frac{ \frac{49}{2} -11 }{\cancel{15}} ) \times \cancel5$

$\sf\longrightarrow \bf median=15 + (24.5 -11 )\times 3$

$\sf\longrightarrow \bf median=15 + \frac{ (24.5 -11)}{3}$

$\sf\longrightarrow \bf median=15 + \frac{13.5}{3}$

$\sf\longrightarrow \bf median=15 + 4.5$

$\sf\longrightarrow \bf \boxed{\red{median=19.5}}$

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$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$

#answerwithquality & #BAL