plz solve this it is urgent
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In triangle ADB and triangle ABC
=> AD=BC (Given)
=> AB=AB (Common)
=> angle DAB = angle CBA (angles on same line are of 90°)
so, by RHS triangle ADB = triangle ABC
HENCE PROVED!!
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=> AD=BC (Given)
=> AB=AB (Common)
=> angle DAB = angle CBA (angles on same line are of 90°)
so, by RHS triangle ADB = triangle ABC
HENCE PROVED!!
Hope it helps uhh!!
and wish uhh a very...
(belated)
♡ HAPPY ♡
NEW YEAR
2019
/\_ヘ/ヽ
/ (_ (⌒厂ヽ
| \ノ
土 ● o ● 土
乂____ 乂
/ \y/ヽ
| ̄|)(| ̄ |
(_ノ_ヽ_)
(Y)(Y)
 ̄  ̄
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triangle ADB --------- triangle BCA
AD = BC____________Side
angle DAB = angle CBA ___________Angle
AB = AB (common) ____________side
- So by SAS criteria its congruent.
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