plz solve this it's from class 10 ( pair of linear pair in 2 variables)
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Step-by-step explanation:
Let's us consider the two no. are x&y
Given:
x/y=5/6
x*6=y*5
6x-5y=0.....(i)
If 8 is subtracted from each of the no. then the ratio is 4:5.
5x-4y=8.....(ii)
from eqn. (i)
x=5y/6
Substitute the value of x from eqn.(ii)
5(5y/6)-4y=8
y=48
Substitute the value of y in the eqn.(i)
6x-5(48)=8
6x=240
x=40
Hence, the no. are 40&48
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