Math, asked by aanchal828564, 1 year ago

plz solve this it's urgent ​

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Answered by Abhishek474241
0
\huge{\mathfrak\color{brown}{HEY\:FRIEND}}



\color{brown}{HERE\:IS\:YR\:ANS}


\underline\color{Green}{REAL\:NO}


let n is be any positive integer 3q,3q+1and3q+2

then a+bq
let r =0
n=3q
thn 3q
it is clearly divisible by 3


case2

let r=1

thn
n= 3q+1
n+2=3q+3
n+2=3(q+1)

thn it is clearly divisible by 3

case3
let r =2
n=3q+2
n+1=3q+3
n+1=3(q+1)

thn it is clearly divisible by 3


hence one and only one of is divisible by 3


\fbox\color{brown}{HOPE\:IT\:HELPS}


\huge{\mathfrak{THANKS}}



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aanchal828564: why you add 2 in 'n' in case 2 I
aanchal828564: don't understand
aanchal828564: in case 2 and 3 these numbers are not divisible by 3
aanchal828564: plz follow me back
Abhishek474241: hey dear the next two cases also divisible by 3 on first n,n+2,n+3
Abhishek474241: n+1
aanchal828564: why you do n+1
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