plz solve this it's urgent
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let n is be any positive integer 3q,3q+1and3q+2
then a+bq
let r =0
n=3q
thn 3q
it is clearly divisible by 3
case2
let r=1
thn
n= 3q+1
n+2=3q+3
n+2=3(q+1)
thn it is clearly divisible by 3
case3
let r =2
n=3q+2
n+1=3q+3
n+1=3(q+1)
thn it is clearly divisible by 3
hence one and only one of is divisible by 3
aanchal828564:
why you add 2 in 'n' in case 2 I
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