plz solve this,its urgent!!!!!!
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1
Hello dear friend
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Hey friend!!
Here is your answer:-
It can be observed that BCD is a straight line.
So,
Angle ACD + Angle ACB = 180° {linear pair of angles}
130° + ACB = 180°
ACB = 180-130
ACB = 50°.
In ∆ ABC,
Given,
AB = AC
So,
Angle ABC = Angle ACB {Angle opposite to equal side are equal}
Angle ABC = 50°
Now,
A+B+C = 180°
A+50+50 = 180°
A+100 = 180°
Angle A = 180-100
Angle A = 80°
Hope it helps you.
If you satisfied mark it brainliest.
Here is your answer:-
It can be observed that BCD is a straight line.
So,
Angle ACD + Angle ACB = 180° {linear pair of angles}
130° + ACB = 180°
ACB = 180-130
ACB = 50°.
In ∆ ABC,
Given,
AB = AC
So,
Angle ABC = Angle ACB {Angle opposite to equal side are equal}
Angle ABC = 50°
Now,
A+B+C = 180°
A+50+50 = 180°
A+100 = 180°
Angle A = 180-100
Angle A = 80°
Hope it helps you.
If you satisfied mark it brainliest.
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