Question

PLZ SOLVE THIS ITS URGENT ...
NO SPAMS....​

Answer 1

Hope this attachment may help you. ..

Answer 2

Answer:

In ∆ABC

we have to prove that ∆ABP=∆APC

AP=AP(Common)

AB=AC(given)

BP=BC(AP is perpendicular bisector of BC)

So, by RHS rule ∆ABP=∆APC

BY CPCT ANGLE B = ANGLE C