Question

Plz solve this Linear equations 4p +3q = 14 and 3p + 4q= 23 by elimination method

Answer 1

Answer:

q = 50/7; p = -13/7

Step-by-step explanation:

4p + 3q = 14.............(1)

3p  + 4q = 23...........(2)

Multiply equation (1) by 3 and equation (2) by 4 to make (p) term equal

So,

12p + 9q = 42...................(3)

12p + 16q = 92.................(4)

Subtract (3) from (4)

We get,

16q - 9q = 92 - 42

7q = 50

q = 50/7

Now put q = 50/7 in equation (1)

$4p + 3(\frac{50}{7}) = 14\\\\4p + \frac{150}{7} = 14\\\\\frac{28p+150}{7} = 14$

28p + 150 = 14 x 7

28p + 150 = 98

28p = 98 - 150

28p = (-52)

p = (-52)/28

p =   -13/7

HOPE IT HELPS YOU

Answer 2

Answer:

p= -13/7

q= 50/7

Step-by-step explanation:

Hii mate :-)

4p+3q=14

Multiplying both sides by 4, we get

=>16p+12q=56   ......(1)

3p+4q=23

Multiplying both sides by 3, we get

=>9p+12q=69    ........(2)

Subtracting (2) from (1), we get

7p= -13

=>p= -13/7

Putting this value of p in (2), we get

9(-13/7) + 12q=69

=>(-117/7) + 12q=69

=>12q=69+(117/7)

=>12q=(483+117)/7

=>12q=600/7

=>q=600/(7x12)

=>q=50/7

HOPE IT HELPS,

PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.