plz solve this ..marked question
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Given angles 72° 53'51" and 41° 22'50 "
Let the third angle be x
Sum of angles of traingle = 180°
Then,
72° 53'51" + 41° 22'50 " + x= 180
x = 180 - (72° 53'51" + 41° 22'50 ")
=> 180 - (113° 75' 101")
Since 1° = 60' and 1' = 60"
=> x = 180° - ( 114° 16' 51")
=> x = 65° 43' 9"
It is equal to 1.1470 rad
Let the third angle be x
Sum of angles of traingle = 180°
Then,
72° 53'51" + 41° 22'50 " + x= 180
x = 180 - (72° 53'51" + 41° 22'50 ")
=> 180 - (113° 75' 101")
Since 1° = 60' and 1' = 60"
=> x = 180° - ( 114° 16' 51")
=> x = 65° 43' 9"
It is equal to 1.1470 rad
yuvrajkj:
oh wait
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please mark as brilliant ☺☺
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