Question

plz solve this math........​

Answer 1

Answer:

we will reverse the A.P

253,248..13,8,3

d=-5

a=253

a20=a+19d

a20=253+19×-5

a20=253-95

=158

hope it helps..

please mark me as brainliest..

Answer 2

The given AP is 3,8,13,....,253

We need to find the 20th term from the last

So basically we need to find the 20th term of the reverse of this AP

that is we need to find the 20th term of the AP 253,248,243,.....,3

Here first term a = 253

common difference d = -5

$a_{n}$ = $a_{} + (n-1)d$

$a_{20} = 253 + (20-1)*(-5)$

$a_{20} = 253 - 95$

$a_{20} = 158$

That is, the 20th term from the last of the given AP is 158

HOPE IT HELPS !!