Question

Plz solve this!!!!!!!!!!Maths

Answer 1

$\textbf {Hey mate! Here's the solution.... }$⤵⤵

${x}^{2} + x - (a + 2)(a + 1)=0$

Here the middle term is x
which can be also written as 1x...so,in the next step I have written the middle term as.....
( (a+2)-(a+1))x
=(a+2-a-1)x
=1x
so, here we get that ( (a+2)-(a+1))x=x
Thus, we can replace x by
( (a+2)-(a+1))x

$= >{x}^{2} + {((a + 2) - (a + 1))}x - (a + 2)(a + 1)=0$

$=> {x}^{2} + (a + 2 )x - (a + 1)x - (a + 2)(a + 1)=0$

$=> x(x + a + 2) - (a + 1)(x + a + 2)=0$

$=> (x + a + 2)(x - a + 1)=0$
so,
either
$(x + a + 2) =0$
$=> x =-a-2$

or,
$(x - a + 1) =0$
$=> x =a-1$

$\textbf{I hope it helps you....}$❤❤