Question

plz solve this....
maths (个_个)
class 11 ​

Answer 1

$\large\underline\purple{\bold{Solution :- }}$

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$\bf \: The \: given \: is$

$\tt \: 1, 11, 111, 1111, 11111, 111111,$

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$\bf \: So, \: {6}^{th} \: term \: is \: 111111$

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$\bf \: Also, \: 111111 \: can \: be \: re - written \: as$

$\tt \:  = \dfrac{1}{9} \times 999999$

$\tt \:  = \dfrac{1}{9} (1000000 - 1)$

$\tt \:  = \dfrac{ {10}^{6} - 1 }{9}$

$\implies \boxed{ \red{ \bf \: 111111 = \dfrac{ {10}^{6} - 1 }{9} }}$

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$\bf \: Also, \: 111111 \: can \: be \: re - written \: as$

$\tt \:  = \: 1000000 + 100000 + 10000 + 1000 + 100 + 10 + 1$

$\tt \: = \:   {10}^{6} + {10}^{5} + {10}^{4} + {10}^{3} + {10}^{2} + 10 + 1$

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$\bf \: So$

$\boxed{ \purple{:  \implies \rm \: option \: (d) \: is \: not \: correct}}$