Question

plz solve this.............no cheping cheping..​

Answer 1

HEY MATE YOUR ANSWER IS HERE

GIVEN EQUATION IS ,

RATE OF FLOW ,

$\frac{v}{t} = \frac{\pi p r ^{4} }{8 η l}$

NOW ,

DIMENSION FORMULA OF L.H.S

$( \frac{v}{t} ) \: = ( {l}^{3} \: {t}^{ - 1} )$

DIMENSIONAL FORMULA OF R.H.S

$\frac{\pi p r ^{4} }{8 η l} = ( \frac{(ml ^{ - 1} \: t ^{ - 2} )(l ^{4}) }{ml ^{ - 1} \: t ^{ - 1} )(l )} \\ \\ = ( {t}^{ - 1} l ^{3} )$

IT IS CLEAR THAT LHS = RHS

THUS THE GIVEN FORMULA IS DIMENSIONALLY CORRECT

THANKS FOR UR QUESTION HOPE IT HELPS

KEEP SMILING ☺️✌️

Answer 2

Explanation:

refer to attachment hope its help uhh