Physics, asked by Anonymous, 9 months ago

plz solve this.............no cheping cheping..​

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Answered by Anonymous
15

HEY MATE YOUR ANSWER IS HERE

GIVEN EQUATION IS ,

RATE OF FLOW ,

 \frac{v}{t}  =  \frac{\pi p  r ^{4} }{8 η l}  \\  \\

NOW ,

DIMENSION FORMULA OF L.H.S

( \frac{v}{t} ) \:  = ( {l}^{3}  \:  {t}^{ - 1} ) \\  \\

DIMENSIONAL FORMULA OF R.H.S

   \frac{\pi p  r ^{4} }{8 η l}   = ( \frac{(ml ^{ - 1}  \: t ^{ - 2} )(l ^{4}) }{ml ^{ - 1}  \: t ^{ - 1} )(l )}   \\  \\  = ( {t}^{ - 1} l ^{3} )

IT IS CLEAR THAT LHS = RHS

THUS THE GIVEN FORMULA IS DIMENSIONALLY CORRECT

THANKS FOR UR QUESTION HOPE IT HELPS

KEEP SMILING ☺️✌️

Answered by Anonymous
4

Explanation:

refer to attachment hope its help uhh

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