Question

plz solve this no spam answers

Answer 1

Q1). tan =9/6(Perpendicular/Base),
tan= 3/2
P= 3, B= 2,
H=√3*3+2*2
=√9+4
=√13

Therefore,
sin = p/h,
=3/√13
=3√13/13

cos = b/h
=2/√13
=2√13/13

Hence,

(sin- cos) / (sin+cos)
(3√13 / 13 - 2√13 / 13) / (3√13 /13+2√13 /13)
(√13 / 13) / (5√13 / 13)
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