plz solve this. No useless answer
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C (eff)=(2×4)/(2+4)=8/6 ×10^(-6) F
So
Q=C(eff)×V
Hence,
Q=(8/6)×10^(-6)×1200=1600×10^(-6) C
So V across 2uF=[1600×10^(-6]/[2×10^(-6)]
Therefore Ans --800V ans.
So
Q=C(eff)×V
Hence,
Q=(8/6)×10^(-6)×1200=1600×10^(-6) C
So V across 2uF=[1600×10^(-6]/[2×10^(-6)]
Therefore Ans --800V ans.
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