Question

plz solve this. No useless answer

Answer 1

C (eff)=(2×4)/(2+4)=8/6 ×10^(-6) F

So

Q=C(eff)×V

Hence,
Q=(8/6)×10^(-6)×1200=1600×10^(-6) C

So V across 2uF=[1600×10^(-6]/[2×10^(-6)]

Therefore Ans --800V ans.