plz solve this numerical. it's of class 10 of physics of the chapter electricity.
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Hey
Resistance ( R) = 26 Ω
length (l) = 1 m
Temperature (T) = 20°C = 293.15 K
Diameter = 0.3 mm = 0.3 x 10⁻³ m
Radius = 0.3/2 x 10⁻³ = 0.15 x 10⁻³ m
Area ( A) = π r²
= 3.14 x 0.15 x 0.15 x 10⁻⁶
= 0.7065 x 10⁻⁶m²
Resistivity(ρ) = ?
R = ρl/A
ρ = R X A / l
ρ = 26 x 0.7065 x 10⁻⁶ / 1
ρ = 1.8369 ohm / m
Resistance ( R) = 26 Ω
length (l) = 1 m
Temperature (T) = 20°C = 293.15 K
Diameter = 0.3 mm = 0.3 x 10⁻³ m
Radius = 0.3/2 x 10⁻³ = 0.15 x 10⁻³ m
Area ( A) = π r²
= 3.14 x 0.15 x 0.15 x 10⁻⁶
= 0.7065 x 10⁻⁶m²
Resistivity(ρ) = ?
R = ρl/A
ρ = R X A / l
ρ = 26 x 0.7065 x 10⁻⁶ / 1
ρ = 1.8369 ohm / m
Answered by
2
Answer:
The resistivity of the metal at 20°C is
1.84 x 10 rest to the power -6m
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