Question

plz solve this one ​

Answer 1

$\bold\purple{\boxed{ANSWER=>n=0}}$

$\bold\green{\underline{\underline{SOLUTION}}}$

$⟹8 \times {2}^{n + 2} = 32 \\ \\ ⟹ {2}^{n + 2} = \frac{32}{8} \\ \\ ⟹ {2}^{n + 2} = 4 \\ \\ ⟹ {2}^{n + 2} = {2}^{2} \\ \\ ⟹n + 2 = 2 \\ \\ ⟹n = 2 - 2 \\ \\ ⟹n = 0$

Answer 2

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$\tt\it\bf\huge\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{ANSWER==>}}}}$

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8 * 2^(n+2) = 32

2³ * 2^(n+2) = 2^5

2^(3+n+2)=2^5

3+n+2=5

5+n=5

n=>5-5=0

Hence, n =0

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