plz solve this one...........
Attachments:
mrOogway:
Is the answer cota
Answers
Answered by
1
We know,
cos(2π + α) = sinα
cosec(π - α) = cosecα
tan(π/2 +α) = -cotα
sec(π/2 + α) = -cosecα
sin(3π/2 - α) = -cosα
cot(2π-α) = -tanα
THUS, the equation becomes = cosα × cosecα ×(-cotα)/(-cosecα) (-cosα)(-cotα)
= 1
Hence, the aspnswer is 1.
cos(2π + α) = sinα
cosec(π - α) = cosecα
tan(π/2 +α) = -cotα
sec(π/2 + α) = -cosecα
sin(3π/2 - α) = -cosα
cot(2π-α) = -tanα
THUS, the equation becomes = cosα × cosecα ×(-cotα)/(-cosecα) (-cosα)(-cotα)
= 1
Hence, the aspnswer is 1.
thanks
cos (2π. +alpha) = cos alpha. error
Similar questions