Question

plz solve this one immediately

Q.6 Two particles were projected one by one with the same initial velocity from the same point on level ground. They follow the same parabolic trajectory and are found to be in the same horizontal level, separated by a distance of Im, 2 seconds after the second particle was projected. Assume that the horizontal component of their velocities is 0.5 m/s. Which of the following statements will be true about

their motion ?

(A) The horizontal range of the parabolic path is 3 m. (B) The maximum height for the parabolic path is 45 m. (C) The total time of flight in the parabolic path for each particle = 4s (D) The horizontal range of the parabolic path is 6 m.​

Answer 1

Answer:

45

Step-by-step explanation:

$Distance travelled by 2nd particle in 2s = 0.5×2=1m\\Horizontal range =1+1+1=3m\\Flight time =4+2=6s\\6=\frac{2usinθ}{g}usinθ =30\\H=\frac{u^{2} sin^{2}θ}{2g}\\ = \frac{900}{2*10} = 45$

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