Question

plz solve this one it is emergency

Answer 1

here is your polynomial of rank 3

Answer 2

$( \sqrt{3} {a}^{4} + 2 \sqrt{3} {a}^{3} + 3 {a}^{2} - 6a) \div 3a \\ \frac{1}{ \sqrt{3} } {a}^{3} + 2 {a}^{2} + \sqrt{3} a - 2$

so answer is

$\frac{1}{ \sqrt{3} } {a}^{3} + 2 {a}^{2} + \sqrt{3} a - 2 \:$