Question

plz solve this one!!!
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SATISFYING ANSWER WILL BE MARKED as brainliest....​

Answer 1

Answer:

Step-by-step explanation:

positive x-axis (east) = i

negative x-axis (west) = -i

positive Y-axis (north) = j

negative y-axis (south) = j

and north - east direction means, vector 45° with x-axis . so, (cos45° i + sin45° j)

now let's apply all above concept here.

A ball is acted upon by the following velocities

(i) 3 metre per sec due east i.e.,  = 3i

(ii) 11 metre per sec due to south i.e.,  = -11j

(iii) 5 root 2 metre per sec due north-east. i.e., = 5√2(cos45° i + sin45° j) = (5i + 5j)

now resultant velocity of ball =

= 3i + (-11j) + (5i + 5j)

= 8i - 6j

so, magnitude of resultant velocity of ball = √{8² + (-6)²} = 10m/s

direction of resultant velocity, tanα = |-6/8| = tan37° ⇒ α = 37°