Question

plz solve this one too.

if don't know the answer plz leave and those who can answer welcome​

Answer 1

when the object is infinity U= -infinityV=2.3CMBY USING FOCAL LENS FORMULA1/F= 1/V-1/U1/FMAX = 1/2.3 - 1/INFINITY

SO fmax is zero

• then when the object is infinity The parallel rays forms makes the ciliary muscle relax and focal length maximum value which is equal to the distance of 2.3 CM here the ciliary muscle releaxed so the FL is increase.
• when the focused the ciliary muscles strained so the focal length decreases
• U= -25CMV=2.3CM USE LENS FORMULA 1/F= 1/V-1/U=1/2.3 -1/25=10/23 -1/25=250+23/575 273/575=2.1 CM
• if object is placed in between the infinity and the point at least the distance of the eye vision the length adjust its focal length between 2.3 cm to 2.1 CM

1. thank u ❤

• i hope this might be helpfull to u and i hope u will understand this.
• will u mark this ans as brainliest and u look greate