Question

plz solve this ....physics ​

Answer 1

Answer:

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Answer 2

Answer:

Given:

Object distance = 20 cm

Image distance = 15 cm

To find:

• Magnification
• Type of mirror used

Calculation:

Object distance is always taken in negative , hence in this case will be -20 cm. Image distance will be positive because virtual image is produced.

$magnification = - \dfrac{v}{u}$

$= > magnification = - \dfrac{15}{( - 20)}$

$= > magnification = 0.75$

Since magnification is less than 1 and is positive , we can say that the image is erect and diminished. Also the Question says that virtual image is produced.

Hence the mirror used is Convex Mirror .