Question

plz solve this plz do not report this question

Answer 1

This is the answer of question 29

Answer 2

Hey !!

Here's your answer ..
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Q. 29
Ans.

=>
$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ \\ = > \: \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \: + \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ = > \frac{ {( \sqrt{3} - \sqrt{2} )}^{2} }{ 3 - 2} + \frac{ {( \sqrt{3} + \sqrt{2} ) }^{2} }{3 - 2} \\ \\ = > \: \: \frac{3 - 2 \sqrt{6} + 2 }{1} + \frac{3 + 2 \sqrt{6} + 2 }{1} \\ \\ = > \: \: \frac{3 - 2\sqrt{6} + 2 + 3 + 2 \sqrt{6} + 2}{1} \\ \\ = > \: \: 5 + 5 \\ \\ = > \: \: 10 \\ \\ = = = = = = = = = = = = \\ \\ 30. \\ answer \\ \\ x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ \\ x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{ 3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ x = \frac{ {( \sqrt{3} + \sqrt{2} )}^{2} }{3 - 2} \\ \\ x = 3 + 2 \sqrt{6} + 2 \\ \\ x = 5 + 2 \sqrt{6} \\ \\ (1) \: \: \frac{1}{x} = \frac{1}{5 + 2\sqrt{6} } \\ \\ \frac{1}{x} = \frac{1}{5 + 2 \sqrt{6} } \times \frac{5 - 2 \sqrt{6} }{5 + 2 \sqrt{6} } \\ \\ \frac{1}{x} = \frac{5 - 2 \sqrt{6} }{25 - 24} \\ \\ \frac{1}{x} = 5 - 2 \sqrt{6} \\ \\ add \: \: x \: \\ \\ x + \frac{1}{x} = 5 + 2 \sqrt{6} + 5 - 2 \sqrt{6} \\ \\ x + \frac{1}{x} = 10 \\ \\ take \: \: square \: \: on \: \: both \: \: side \\ \\ {(x + \frac{1}{x} )}^{2} = {(10)}^{2} \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2x \times \frac{1}{x} = 100 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 100 - 2 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 98 \\ \\ \\ (2) {x}^{2} + \frac{1}{ {x}^{2} } = 98 \\ \\ take \: \: sqaure \: \: on \: \: both \: side \\ \\ {( {x}^{2} + \frac{1}{ {x}^{2} } )}^{2} = {(98)}^{2} \\ \\ {x}^{4} + \frac{1}{ {x}^{4} } + 2 {x}^{2} \times \frac{1}{ {x}^{2} } = 9604 \\ \\ {x}^{4} + \frac{1}{ {x}^{4} } = 9604 - 2 \\ \\ {x}^{4} + \frac{1}{ {x}^{4} } = 9602 \\ \\ = = = = = = = = = = = =$
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