Question

plz solve this plzzz....​

Answer 1

Answer:

I don't know

Explanation:

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Answer 2

vapor pressure of CHCl3 Pa° = 200 mm of Hg

vapor pressure of CH2Cl2 Pb° = 415 mm of Hg

mass of CHCL3=25.5g

molar mass CHCL3 =119.38g

moles CHCL3

= mass / molar mass

= 25.5/119.38

=0.21

mass of CH2CL2=40g

molar mass CHCL3 =85g

moles CHCL3

= mass / molar mass

= 40/85

=0.47

total moles = 0.47+0.21=0.68

mole fraction(Xa) CHCL3

= moles of a/ total moles

= 0.21/0.68

=0.3

mole fraction(Xa) CH2CL2

= moles of a/ total moles

= 0.47/0.68

=0.7

P total

= Pa° xa + Pa° xb

=200(0.3) + 415 (0.7)

=60+290.5

=350.5

mole fraction of component a in vapor phase

pa = y 1 P total

y 1 = pa /P total

y 1=Pa° xa /350.5

y 1=60 /350.5

y 1=0.2

y 2 = 290 .5/350.5

y 2= 0.8