Math, asked by sowmiyayahoocom, 1 year ago

plz solve this
plzzzz ans 10th q

Attachments:

sowmiyayahoocom: can u

Answers

Answered by Anonymous
21
hii mate!!

↪Let the actual price of the TV be Rs. 'x' and of the fridge be Rs. 'y'.

↔Situation -1

By selling the TV at 5 % gain and fridge at 10 % gain, the shopkeeper gains Rs. 2000.

⇒ 5x/100 +  10y/100 = 2000

⇒ x/20 + y/10 = 2000/1

Taking the L.C.M. of the denominator and then solving it, we get.

⇒ (x + 2y)/20 = 2000

⇒ x + 2y = 40000  ...........................(1)

↔Situation - 2

By selling the TV at 10 % gain and fridge at 5 % loss, the shopkeeper gains Rs. 1500. The loss is indicated with the negative sign.

⇒ 10x/100 - 5y/100 = 1500

⇒ x/10 - y/20 = 1500/1

Taking the L.C.M. of the denominator and then solving it, we get.

⇒ (2x - y)/20 = 1500

⇒ 2x - y = 30000  ........................(2)

↪Now, multiplying the (1) by 2, and then subtracting 2 from it, we get.

First Multiplying (1) by 2 = 2*[(x + 2y) = 40000]

⇒ 2x + 4y = 80000

Now, subtracting (2) from the above.

      2x + 4y = 80000
      2x  -  y  = 30000 
    -      +       -
   ________________

             5y  = 50000
__________________

⇒ 5y = 50000

⇒ y = 50000/5

⇒ y = 10000

The actual price of fridge is Rs. 10000.

⭐Now putting the value of y = 10000 in (1), we get.

⇒ x + 2y = 40000

⇒ x + (2*10000) = 40000

⇒ x = 40000 - 20000
 
⇒ x = 20000

Hence, the actual price of TV is Rs. 20000 and actual price of fridge is Rs. 10000.

⭐hope it helps !!☺☺☺☺

sowmiyayahoocom: u did it in your own? ?????
Anonymous: yes
sowmiyayahoocom: plz can u open inbox for me
Anonymous: okay
sowmiyayahoocom: so that I can show the same ans like you
Anonymous: hm
sowmiyayahoocom: now ok
sowmiyayahoocom: thanks a lottt
sowmiyayahoocom: I got the ans tq soooo much for your ans really good
Anonymous: welcome
Answered by siddhartharao77
25
Let the cost price of the TV be x and the cost price of the Fridge be y.

(1)

Given that Selling a Tv at 5% gain and Fridge at 10% gain shopkeeper gains 2000.


= > 5x/100 + 10y/100 = 2000

= > 5x + 10y = 200000

= > x + 2y = 40000     -------------- (1)


(2)

Given that if he sells the TV at 10% gain and the fridge at 5% loss. He gains 1500.



= > (10x/100) - (5y/100) = 1500

= > 10x - 5y = 150000

= > 2x - y = 30000     ------------ (2)



On solving (1) * 2 & (2), we get

2x + 4y = 80000

2x - y = 30000

------------------------

      5y = 50000

        y = 50000/5

        y = 10000.


Substitute y = 10000 in (1), we get

= > x + 2y = 40000

= > x + 2(10000) = 40000

= > x + 20000 = 40000

= > x = 40000 - 20000

= > x = 20000.


Therefore the actual price of TV = 20000.

Therefore the actual price of Fridge = 10000.




Hope this helps!

siddhartharao77: :-)
sowmiyayahoocom: thanks a lottt for your precious help
Anonymous: fab ^_^ dude
siddhartharao77: Thank you!...
sowmiyayahoocom: siddhartharao can u help me again :-(
Similar questions