plz solve this plzzzzz
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GOOD MORNING!!!!
L.H.S
let theta = x
( Tanx + Sec x - 1 )
______________
( Tan x - Sec x + 1 )
MULTIPLY Numerator and DENOMINATOR by ( Tan x + Sec x - 1 )
we get
=>
{ Tan x + Sec x - 1 }²
________________
{ Tan x - Sec x + 1 } × { Tan x + Sec x - 1}
=>
Tan² x + ( sec x -1 )² + 2Tan x ( sec x -1 )
____________________
Tan²x - ( sec x - 1 )²
=>
Tan² x + Sec²x +1 -2sec x +2Tan x ( secx-1)
___________________
Tan² x - Sec² x - 1 + 2secx
=>
-1 + Sec²x + Sec² x + 1 - 2secx + 2Tanx(secx - 1 )
____________________
Sec²x -1 - Sec² x + 2secx -1
=>
2 secx { Sec x - 1 }+ 2Tanx ( sec x - 1)
___________________
2( Sec x - 1 )
=>
Tan x + Sec x
= (1 + Sinx) / Cosx
Formula used
1 + Tan² x = Sec² x
And
( a + b )² = a² + b² + 2ab
2)
Cos 2x = Cos ( 60 - 30 )
Cos 2x = Cos 30
2x = 30
So, sin ( 2x ) = Sin (30 ) = 1/2
Formula used
Cos ( A - B ) = Cos A × Cos B + SinA × SinB
L.H.S
let theta = x
( Tanx + Sec x - 1 )
______________
( Tan x - Sec x + 1 )
MULTIPLY Numerator and DENOMINATOR by ( Tan x + Sec x - 1 )
we get
=>
{ Tan x + Sec x - 1 }²
________________
{ Tan x - Sec x + 1 } × { Tan x + Sec x - 1}
=>
Tan² x + ( sec x -1 )² + 2Tan x ( sec x -1 )
____________________
Tan²x - ( sec x - 1 )²
=>
Tan² x + Sec²x +1 -2sec x +2Tan x ( secx-1)
___________________
Tan² x - Sec² x - 1 + 2secx
=>
-1 + Sec²x + Sec² x + 1 - 2secx + 2Tanx(secx - 1 )
____________________
Sec²x -1 - Sec² x + 2secx -1
=>
2 secx { Sec x - 1 }+ 2Tanx ( sec x - 1)
___________________
2( Sec x - 1 )
=>
Tan x + Sec x
= (1 + Sinx) / Cosx
Formula used
1 + Tan² x = Sec² x
And
( a + b )² = a² + b² + 2ab
2)
Cos 2x = Cos ( 60 - 30 )
Cos 2x = Cos 30
2x = 30
So, sin ( 2x ) = Sin (30 ) = 1/2
Formula used
Cos ( A - B ) = Cos A × Cos B + SinA × SinB
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