Plz solve this problem ( 10th one )
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Lets assume that one integer = " x "
Then ,
other integer = 20 - x
\frac{20- x}{x} = -3
20 - x = -3x
20 = -3x +x
20 = -2x
-2x = 20
x = 20 ÷ -2
x = -10
Larger number = 20 - x
= 20-(-10)
= 20+10
= 30
smaller number = -10
Then ,
other integer = 20 - x
\frac{20- x}{x} = -3
20 - x = -3x
20 = -3x +x
20 = -2x
-2x = 20
x = 20 ÷ -2
x = -10
Larger number = 20 - x
= 20-(-10)
= 20+10
= 30
smaller number = -10
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