Question

plz solve this problem ​

Answer 1

$\huge\bigstar\mathfrak\pink{\underline{\underline{SOLUTION:}}}$

The prime factorisation of 392 is,

392= 2×2×2×7×7

Since, the prime factor 7 doesn't occur in the group of 3, so

392 is not a perfect cube.

Now,

392 must be multiplied by 7 in order to make it a perfect cube.

=) 392× 7= 2×2×2×7×7×7

=) 2744= 2×2×2×7×7×7

$3 \sqrt{2744} = 3 \sqrt{2 \times2 \times 2 \times 7 \times 7 \times 7} \\ \\ = > 2 \times 7 = 14$

hope it helps ☺️