plz solve this problem
Answers
Energy of a photon , E = hv where h = planks constant = 6.6 × 10^34 Js and v = frequency of the phonton.
100 watt bulb emits photons of light having frequency 300 hz
Here Power = Energy / time
100 wt bulb means 100 joules of energy radiate out in one second.
Thus , In one second Energy radiate = 100 joules
In 1 minutes , Energy radiate = 100 × 60 joules
In 10 min , Energy radiate = 100 × 60 × 10 joules
Thus Energy radiate out in 10 min = 60000 joules
=> E1 = 60000 Joules
Let n = number of photons emit out
Now Energy of a photon , E = hv
Energy of n photons , E2 = n × h × v
=> E2 = n × 6.6 × 10^ - 34 × 300 Joules
According to problem
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E2 = E1
=> n × 6.6 × 10^ - 34 × 300 J = 60000 J
=> n × 19.8 × 10^ - 32 J = 60000 J
=> n = 60000 / 1.98 × 10 ^ -32
= 10000 / 3.3 × 10 ^ - 32 ( dividing by 6 )
= ( 100000 × 10 ^ 32 ) / 33 ( simply arranging decimals and zeros )
=( 100 / 33 ) × 10 ^ 35
= 3 × 10 ^ 35 ( approx )
You may get different answer....plz make further calculation if find any mistake...