Question

plz solve this problem ​

Answer 1

Answer:

Answer is 6

Step-by-step explanation:

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Answer 2

Question

$\sf \left[ \begin{array}{c c c} 4 & -3&7 \\-3 & 5&6\\7&x&9\end{array}\right]$

To Find

Value of x

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Option (c) is correct

For Symmetric matrix :

A=A'

[A'=Transpose]

Transpose means changing the elements of rows and columns

Now, we find A'

$A'=\sf \left[ \begin{array}{c c c} 4 & -3&7 \\-3 & 5&x\\7&6&9\end{array}\right]$

Now ,A=A'

We will comparing the elements of A with the A'

$\sf \left[ \begin{array}{c c c} 4 & -3&7 \\ -3 & 5&6\\7&x&9\end{array}\right]=\sf\left[\begin{array}{c c c} 4 & -3&7 \\ -3 &5&x\\7&6&9\end{array}\right]$

On comparing the corresponding elements of both the matrices we obtain x=6

$\sf\huge\therefore\bold{x=6}$