Question

Plz solve this problem

Answer 1

Heya mate!


Your answer-:

There are total 5 days from Tuesday to Saturday.

So,total number of possible outcomes-:

=>5×5

=>25

Now,

Let Tuesday be denoted by t, Wednesday by w, Thursday by The, Friday by F and Saturday by S.

(i)Same day.


Possible outcomes=TT,WW,ThTh,FF,SS

Total=>5

Probability=5/25

=1/5

(ii) Consecutive days-: TW,WT,WTh,ThW,WF,FW,FS,SF


Total outcomes=8

Probability=8/25


(iii) Different days-:

If we subtract 1 from the probability of same days,we will get the probability of the different days.

So,

$= 1 - \frac{1}{5}$


$= \frac{5 - 1}{5}$


$= \frac{4}{5}$






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Answer 2

Answer:

1/5, 8/25, 4/5

Step-by-step explanation:

Given that they visit a shop in the same week{Tuesday to Saturday} = 5 days

Two Customers can visit the shop in 5 * 5 = 25 ways.

∴ Total number of events n(S) = 25.

(i)

Let A be the event of visiting a particular shop on the same day.

A = {Tue,Tue}, {Wed,Wed},{Thu,Thu},{Fri,Fri},{Sat,Sat}

n(A) = 5.

∴ Required probability P(A) = n(A)/n(S)

                                             = 5/25

                                             = 1/5.

(ii)

Let B be the event of visiting a particular Shop on consecutive days.

B = {Tu,We},{We,Th},{Th,Fri},{Fr,Sa},{We,Th},{Th,We},{Fr,Th},{Sat,Fri}

n(B) = 8

∴ Required probability P(B) = n(B)/n(S)

                                            = 8/25.

(iii)

P(will visit on different days) = 1 - P(will reach on same day)

                                               = 1 - 1/5

                                               = 4/5

Hope it helps!