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kinetic energy of 5 moles O2 at 27^0 C
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Kinetic energy of the ideal gas can be calculated as
Kinetic energy = {3*n*R*T} / 2
where,
n = number of moles
R = gas constant
T = temperature in kelvin
We have above is, n = 5 moles of N
R = 8/314,
and T = 27 + 273 (to convert celsius to kelvin, add 273)=300.
Kinetic energy = {3*5*8.314*300} / 2
= 18,706.05 joules or 18.706 kj
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