plz solve this problem friends
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x2-2ax-4b2+a2
x2-2ax+a2-4b2
(x-a)2-4b2
(x-a)2-2b2
(x-a-2b) (x-a +2b)
x2-2ax+a2-4b2
(x-a)2-4b2
(x-a)2-2b2
(x-a-2b) (x-a +2b)
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Given Equation is x^2 - 2ax - (4b^2 - a^2) = 0
= > x^2 - 2ax - 4b^2 + a^2 = 0
= >x^2 + a^2 - 2ax - 4b^2 = 0
= > (x^2 + a^2 - 2ax) = 4b^2
= > (x - a)^2 = (2b)^2
= > (x - a) = 2b (or) -2b
(i)
= > x - a = 2b
= > x = 2b + a
(ii)
= > x - a = -2b
= > x = -2b + a
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Therefore, the values of x = 2b + a (or) a - 2b.
Hope this helps!
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