Math, asked by Suraj1935, 11 months ago

plz solve this problem immediately plz plz plz plz plz​

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Answers

Answered by pyarip
1

Answer:

LHS

(1-cosA)(1-cosA)/(1+cosA)(1-cosA)

=(1-cosA)^2/1-cos^2A

=1+cos^2A-2cosA/sin^2A

=1/sin^2A+cos^2A/sin^2A-2cosA/sin^2A

=Cosec^2A+cot^2A-2×cotA×cosecA

=(cosecA-CotA)^2

RHS:

(CosecA-cotA)^2

thereforeLHS=RHS

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