Question

Plz solve this problem now​

Answer 1

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Answer 2

$x+\frac{1}{x} =4$

Squaring both sides :

$(x+\frac{1}{x})^2=(4)^2\\\\x^2+\frac{1}{x^2}+ 2 *x*\frac{1}{x}=16\\\\x^2+\frac{1}{x^2}+2=16\\\\x^2+\frac{1}{x^2}=16-2\\\\x^2+\frac{1}{x^2}=14$