Question

Plz solve this problem now.​

Answer 1

✯✯ QUESTION ✯✯

If x-2 is a factor of x³-5x²+ax-7 the find the value of a..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{x-2=0}$

$\longmapsto\tt{x=2}$

➥Putting x = 2 : -

$\longmapsto\tt{{x}^{3}-{5x}^{2}+ax-7=0}$

$\longmapsto\tt{{(2)}^{3}-5{(2)}^{2}+a(2)-7=0}$

$\longmapsto\tt{8-5(4)+2a-7=0}$

$\longmapsto\tt{8-20+2a-7=0}$

$\longmapsto\tt{2a=-8+20+7}$

$\longmapsto\tt{2a=19}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{a}\orange{=}\purple{\dfrac{19}{2}}}}$

☛So , The value of a is 19/2...

Answer 2

Question :–

• If (x - 2) is a factor of x³ - 5x² + ax - 7 = 0 , then find the value of 'a' = ?

ANSWER :–

$\\ \: \longrightarrow \: \large { \boxed{ \bold{ a= \dfrac{19}{2} } }}$

EXPLANATION :–

GIVEN :–

• If (x - 2) is a factor of x³ - 5x² + ax - 7 = 0

TO FIND :–

• Value of 'a' = ?

SOLUTION :–

• If (x - 2) is a factor of x³ - 5x² + ax - 7 = 0 , then x = 2 will satisfy the polynomial.

• So that –

$\\ \: \implies \: { \bold{ {(2)}^{3} - 5 {(2)}^{2} + a(2) - 7 = 0 }}$

$\\ \: \implies \: { \bold{ 8 - 5 (4) + a(2) - 7 = 0 }}$

$\\ \: \implies \: { \bold{ 8 - 20 + a(2) - 7 = 0 }}$

$\\ \: \implies \: { \bold{ 8 - 27 + a(2) = 0 }}$

$\\ \: \implies \: { \bold{ - 19 + a(2) = 0 }}$

$\\ \: \implies \: { \bold{ 2a= 19 }}$

$\\ \: \implies \: \large { \boxed{ \bold{ a= \dfrac{19}{2} } }}$

$\\ \rule{220}{2}$