Question

plz solve this problem
tomorrow is my maths paper
so plz help me to solve

I hope you understand

l also mark as branilest ​

Answer 1

Answer:

Note;

If a,b and c are the three consecutive terms of an AP , then the common difference between the terms are same.

ie, b - a = c - b

ie, 2b = a + c

Here, the three consecutive terms of the AP are: (k+2),(4k-6) and (3k-2)

Thus;

=> 2(4k-6) = (k+2) + (3k-2)

=> 8k - 12 = 4k

=> 8k - 4k = 12

=> 4k = 12

=> k = 12/4

=> k = 3

Hence, the required value of k is 3.

Answer 2

AnswEr :

The Value of K is 3 in this AP.

Explanation :

(k + 2), (4k - 6) and (3k - 2) are consecutive terms of an AP.

So the Common Difference will be Equal of the AP. As Arithmetic Progression is a sequence of numbers such that the difference between the consecutive terms is constant.

Let's these Terms be :

• a = (k + 2)

• b = (4k - 6)

• c = (3k - 2)

b - a = d(Difference) __(¡)

c - b = d(Difference) __(¡¡)

_________________________________

From (¡) and (¡¡)

➟ b - a = c - b

➟ b + b = c + a

➟ 2b = c + a

• Plugging the Values

➟ 2 × (4k - 6) = (3k - 2) + (k + 2)

➟ 8k - 12 = 4k

➟ 8k - 4k = 12

➟ 4k = 12

• Cancelling both terms by 4

➟ k = 3

჻ The Value of K is 3 in this AP.