Question

plz solve this problem why you are not helping me plz help​

Answer 1

Answer:

Step-by-step explanation:

Let the digit at ones place = y

Let the digit at tens place = x

original number = 10x + y 

Number formed by reversing the digits =10y + x

On adding original number and Reversed number.

10x+y+10y+x = 110

11x + 11y = 110

11 (x + y ) = 110

x + y = 10

x = 10 - y  eq- (1)

on subtracting 10 from the original number , we get = 10x + y -10

and 4 more than 5 times the sum of digits = 5(x + y) + 4

so,

 

10x + y -10 = 5(x + y) + 4

10x + y -10 = 5x +5y + 4

10x -5x + y -5y = 10 +4

5x - 4y = 14 eq- (2)

putting the value of x in equation (2)

5x - 4y = 14

5×(10-y) - 4y = 14

50-5y-4y =14

-9y = 14 -50

-9y = -36

y = 4

Now

x = 10-y

x = 10 - 4

x = 6

original number or first number = 10x + y  = 10×6+4 = 64

Hope it helps

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