Question

plz solve this problem with clear steps fast...

Answer 1

HEY MAN ✌✌✌✌✌✌↪✌✌ HERE'S THE ANSWER
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$(x + y) ^{2} = {x}^{2} + 2xy + {x}^{2}$
lets put 'a' as x and 1/a as b
$(a + \frac{1}{a} ) ^{2} = (a) ^{2} + 2(a)( \frac{1}{a} ) + ( \frac{1}{a} )$

$(a + \frac{1}{a} ) {}^{2} = {a}^{2} + 2(a)( \frac{1}{a} ) + \frac{1}{ {a}^{2} }$
given that
${a}^{2} + \frac{1}{a {}^{2} } = 23$
therefore we will put the value in the above equation​.
$(a + \frac{1}{a} ) {}^{2} = 23 + 2$
$a + \frac{1}{a} = \sqrt{25}$
a+1/a=5

Answer 2

lets put 'a' as x and 1/a as b
(a + \frac{1}{a} ) ^{2} = (a) ^{2} + 2(a)( \frac{1}{a} ) + ( \frac{1}{a} )

(a + \frac{1}{a} ) {}^{2} = {a}^{2} + 2(a)( \frac{1}{a} ) + \frac{1}{ {a}^{2} }
given that
{a}^{2} + \frac{1}{a {}^{2} } = 23
therefore we will put the value in the above equation​.
(a + \frac{1}{a} ) {}^{2} = 23 + 2
a + \frac{1}{a} = \sqrt{25}
a+1/a=5