Question

plz solve this Q?????????dont spam....​

Answer 1

Answer:

Here's Your Answer:-✨

${x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) \\ \\ = x( {x}^{2} - xy + {y}^{2} ) + y( {x}^{2} + {y}^{2} - xy) \\ \\ = {x}^{3} - {x}^{2} y + x {y}^{2} + x {y}^{2} + {y}^{3} - x {y}^{2} \\ \\ = {x}^{3} + {y}^{3}$

➡ Hence Verified ✨

Answer 2

Step-by-step explanation:

To solve it from LHS side

Let take (x+y)³ to solve this problem

$(x + y {)}^{3} = (x + y)(x + y)(x + y) \\ \\ (x + y {)}^{3} = (x + y)( {x}^{2} + 2xy + {y}^{2} ) \\ \\ (x + y {)}^{3} = {x}^{3} + 2 {x}^{2} y + x {y}^{2} + {x}^{2} y + 2 {x}^{2} y + {y}^{3} \\ \\ (x + y {)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3 {xy}^{2} \\ \\ (x + y {)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y) \\ \\ (x + y {)}^{3} - 3xy(x + y) = {x}^{3} + {y}^{3} \\ \\ (x + y)( {(x + y)}^{2} - 3xy) = {x}^{3} + {y}^{3} \\ \\ (x + y)( {x}^{2} + {y}^{2} + 2xy - 3xy) = {x}^{3} + {y}^{3} \\ \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} + {y}^{2} - xy)$

Hence proved !

To solve it from RHS side

(x + y)³ = (x + y)(x² - xy + y²)

RHS

(x + y)(x² - xy + y²)

x(x² - xy + y²) + y(x² - xy + y²)

x³ - x²y + xy² + x²y - xy² + y³

x³ + y³

LHS = RHS

Hence proved !

Hope this will help you