plz solve this que.
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area of ABCD=area of EFCD
bcz they are on the same base and btw same ||s
diagonal of a parallelogram divides it into two congruent Triangles of equal area area of triangle BCD equal to half the area of ABCD
as the area of ABCD is equal to the area of EFCD
half the area of EFCD will be equal to half the area of ABCD so the area of triangle BCD is equal to half the area of EFCD
as a b c d and e f c d share same base and between same parallels so ED will be equal to AL
and CD is common
so area of ABCD is equal to length into breadth which is equal to DC into al
bcz they are on the same base and btw same ||s
diagonal of a parallelogram divides it into two congruent Triangles of equal area area of triangle BCD equal to half the area of ABCD
as the area of ABCD is equal to the area of EFCD
half the area of EFCD will be equal to half the area of ABCD so the area of triangle BCD is equal to half the area of EFCD
as a b c d and e f c d share same base and between same parallels so ED will be equal to AL
and CD is common
so area of ABCD is equal to length into breadth which is equal to DC into al
Rishabhs111:
thank u ji
i understood
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