Question

Plz solve this que
pzl guys​

Answer 1

$\large\green{\textsf{✩ Verified Answer ✓ }}$

In right angled triangle ABD AB2 = AD2 + BD2 ⇒ AB2 = (12)2 + (16)2 ⇒ AB2 = 144 + 256 ⇒ AB2 = 400 cm2 ⇒ AB = √400 cm2 ⇒ AB = 20 cm Now in ΔABC, a = 48 cm, b = 52 cm, c = 20 cm.

Thus, area of shaded portion of the triangle = (480 – 96) cm² = 384 cm²

$\bf\pink{\textsf{Answered By Miss Ismat}}$

Answer 2

✩ Verified Answer ✓

In right angled triangle ABD AB2 = AD2 + BD2 ⇒ AB2 = (12)2 + (16)2 ⇒ AB2 = 144 + 256 ⇒ AB2 = 400 cm2 ⇒ AB = √400 cm2 ⇒ AB = 20 cm Now in ΔABC, a = 48 cm, b = 52 cm, c = 20 cm.

Thus, area of shaded portion of the triangle = (480 – 96) cm² = 384 cm²

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