Question

plz solve this ques it's urgent.......​

Answer 1

Hêy Fríèñd...

Here is the Solution..

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I Hope This Will Help You ^_^

Answer 2

Hey mate this is your answer.........

In ∆ABC , tan 60° = AB/AC =h/AC

AC=h/√3

In ∆ BDC , tan 30° = x/ED = 1/√3=x/AC

= 1/√3=x/h√3

Now , BE +AE

x+10=h

h/3+10=10=h-h/3

10= 3h-h/3

30=2h

h=15......