Question

plz solve this question​

Answer 1

Q) Volume of one molecule of water if its density is 1 g/cm³

Answer :-

Density of Water given = 1g/cm³

So,

We know 1cm³ =1ml

Thus,

Density = 1 g/ml

$\rule{200}{2}$

Mass of 1 mole of Water will be:-

$= 2 + 16 \\ \\=18 \: grams$

Also,

$1 \: mole = 6.023 \times {10}^{23}molecules$

$\rule{200}{2}$

Therefore,

Mass of 6.023×10²³ molecules of water is 18 gram

Thus,

Applying unitary method:-

Mass of 1 molecule of water will be:-

$= \frac{18}{6.023 \times {10}^{23} } \\ \\ \\ \approx 3 \times {10}^{( - 23)} \: grams$

$\rule{200}{2}$

Now,

We know the density :- 1g/cm³

Therefore

Volume of 1 molecule of water is

$= 3 \times {10}^{( - 23)} {cm}^{3}$

$\rule{200}{2}$