Question

Plz solve this question....

Answer 1

Answer:

I am not looking for an answer on this. Just need to clarify why my approach is failing -

N1+N2+N3, i.e. single digit, double digit, 3 digit

single =2,4,6,8, i.e 4

double = X non-zero =8⋅4=32 X zero =9⋅1=9

Now the confusing part three digit, breaking into 4 cases

X zero zero =9

X nz nz =7⋅8⋅4=224

X z nz =8⋅1⋅4=32

X nz z =8⋅9⋅1=72

Three digit total comes to =9+224+32+72=337. This answer is wrong and it should be 328. What am I missing in the logic? Please suggest.

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Answer 2

Answer:

let be do -2 from the no so that we determines from and we find positive distinct no