Question

plz solve this question
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Answer 1

Answer:

To Prove:

∠1 = ∠4, ∠2 = ∠3

Proof:

In ΔABC,BC = AB (Sides of a rhombus are equal to each other)

∠1 = ∠2 (Angles opposite to equal sides of a triangle are equal)However,

∠1 = ∠3 (Alternate interior angles for parallel lines AB and CD)

∠2 = ∠3

Therefore, AC bisects ∠C

Also,∠2 = ∠4 (Alternate interior angles for || lines BC and DA)

Therefore, AC bisects ∠CAlso,∠2 = ∠4 (Alternate interior angles for || lines BC and DA)∠1 = ∠4

Therefore,

Therefore,AC bisects ∠A

Hence, Proved.

Similarly, it can be proved that BD bisects B and D as well.

Hope it helps you ❣️☑️☑️☑️