Question

plz solve this question...
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Answer 1

$\tan\alpha = \frac{a}{b} \\ \\ = > \frac{ \sin\alpha }{ \cos\alpha } = \frac{a}{b} \\ \\ = > \sin \alpha = a \: and \: \cos \alpha = b$

Now, from the equation :

$\frac{b \sin\alpha - a \cos\alpha }{b \sin \alpha + a \cos \alpha } = \frac{b \times a - a \times b}{b \times a +a \times b} \\ \\ = > 0$

So, option (4) is correct ✔️✔️

I hope it will be helpful for you ✌️✌️

MARK it as brainliest and.....

Fóllòw MË ☺️☺️

Answer 2

Step-by-step explanation:

see the attachment

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