Question

plz solve this question​

Answer 1

AnswEr:

Given:- In ΔABC , AD is perpendicular to BC and AD² = BD.DC

To prove:- ∠ BAC = 90°

Proof:- In right triangles ∆ADB and ∆ADC,

So, Pythagoras theorem should be applied,

Then we have,

AB² = AD² + BD² ----------(1)

AC² = AD² + DC² ---------(2)

Adding equation-----(1) and (2), we get,

AB² + AC² = 2AD² + BD² + DC²

= 2BD.CD + BD² + CD² [ ∵ given AD² =

BD.CD ]

= (BD + CD )²

= BC²

Thus, in ΔABC we have , AB² + AC²= BC²

Hence, ΔABC is a right triangle right angled at A

So, ∠ BAC = 90°

(Showed)

✌Hope it helps you✌

Answer 2

Answer:

Answer in attachment....(3 attachment)

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