plz solve this question
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Let AB be the tower . Let C and D be two points at distances a and b respectively from the base of the tower. Then, AC = a and AD = b. Let angle ACB = 90° - theta. Let h be the height of the tower AB.
In triangle CAB,
tan theta = AB/AC
=> tan theta = h/a....... (i)
In triangle DAB,
tan (90° - theta ) = AB/AD
=> cot theta = h/b........ (ii)
From (i) and (ii),
(tan theta)(cot theta) = h^2/ab
=> 1 = h^2/ab
=> h^2 = ab
=> h = root ab metres.
Hence the height of the tower is root ab metres.
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