Question

plz solve this question

Answer 1

Answer:

angleo BAD = 70°

angleo BAD = 70° angle DCB = 110°

angleo BAD = 70° angle DCB = 110°step by step explanation

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BOD

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140°

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)angle DCB + angle BAD =180° ( sum of the opposite angle of cyclic quadrilateral is 180°)

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)angle DCB + angle BAD =180° ( sum of the opposite angle of cyclic quadrilateral is 180°)so,

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)angle DCB + angle BAD =180° ( sum of the opposite angle of cyclic quadrilateral is 180°)so,angle DCB + 70° = 180°

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)angle DCB + angle BAD =180° ( sum of the opposite angle of cyclic quadrilateral is 180°)so,angle DCB + 70° = 180°angle DCB = 180° -70°

angleo BAD = 70° angle DCB = 110°step by step explanation angle BAD = 1/2 of angle BODso,angle BAD = 1/2 × 140° =70° ( angle at any point on the circle is the half of the angle subtended at the centre)angle DCB + angle BAD =180° ( sum of the opposite angle of cyclic quadrilateral is 180°)so,angle DCB + 70° = 180°angle DCB = 180° -70° angle DCB = 110°

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